∫ (4y)dy =
di jwb -^-
di jwb -^-
= ∫(4y)dy
= [tex]\frac{4}{1~+~1}~.~y^{1~+~1}~+~C[/tex]
= [tex]\frac{4}{2}~.~y^{1~+~1}~+~C[/tex]
= [tex]2~.~y^{2}~+~C[/tex]
= 2y² + C
Penjelasan dengan langkah-langkah:
∫ (4y)dy
[tex] = \frac{4}{1 + 1} {y}^{1 + 1} + c[/tex]
[tex] = \frac{4}{2} {y}^{2} + c[/tex]
[tex] = \frac{ {4y}^{2} }{2} + c[/tex]
[tex] = {2y}^{2} + c[/tex]
[answer.2.content]